Balance the following redox reactions by the ion-electron method:
$(a)$ $MnO_{4(aq)}^- + I_{(aq)}^- \to MnO_{2(s)} + I_{2(s)}$ (in basic solution)
$(b)$ $MnO_{4(aq)}^- + SO_{2(g)} \to Mn_{(aq)}^{2+} + HSO_{4(aq)}^-$ (in acidic solution)
$(c)$ $H_2O_{2(aq)} + Fe_{(aq)}^{2+} \to Fe_{(aq)}^{3+} + H_2O_{(l)}$ (in acidic solution)
$(d)$ $Cr_2O_7^{2-} + SO_{2(g)} \to Cr_{(aq)}^{3+} + SO_{4(aq)}^{2-}$ (in acidic solution)

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $2MnO_{4(aq)}^- + I_{(aq)}^- + H_2O_{(l)} \to 2MnO_{2(s)} + I_{2(s)} + 2OH_{(aq)}^-$
$(b)$ $2MnO_{4(aq)}^- + 5SO_{2(g)} + 2H_2O_{(l)} \to 2Mn_{(aq)}^{2+} + 5HSO_{4(aq)}^- + H_{(aq)}^+$
$(c)$ $H_2O_{2(aq)} + 2Fe_{(aq)}^{2+} + 2H_{(aq)}^+ \to 2Fe_{(aq)}^{3+} + 2H_2O_{(l)}$
$(d)$ $Cr_2O_7^{2-} + 3SO_{2(g)} + 2H_{(aq)}^+ \to 2Cr_{(aq)}^{3+} + 3SO_{4(aq)}^{2-} + H_2O_{(l)}$

Explore More

Similar Questions

$Cr _2 O _7^{2-} \rightarrow Cr ^{3+}_{aq}$
How many moles of $Sn^{2+}$ will be oxidized by $1 \ mol \ Cr_2O_7^{2-}$ into $Sn^{4+}$?

Difficult
View Solution

How many moles of $K_2Cr_2O_7$ will be reduced by $1$ mole of $Sn^{2+}$ ions?

For the redox reaction $MnO_4^{-} + C_2O_4^{2-} + H^{+} \rightarrow Mn^{2+} + CO_2 + H_2O$,the correct coefficients of the reactants for the balanced reaction are respectively $MnO_4^{-}$,$C_2O_4^{2-}$ and $H^{+}$:

Assign $A, B, C, D$ from the given type of reaction:
$5CO(g) + I_2O_5(s) \longrightarrow 5CO_2(g) + I_2(s)$

In alkaline condition $KMnO_4$ reacts as follows:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
Therefore,its equivalent weight will be:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo